Contour integration: Difference between revisions

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hence, this can be represented as, (H is the entire contour, because i said so)
hence, this can be represented as, (H is the entire contour, because i said so)
<math> \oint\limits_{H}\frac{1}{x^2+1} \mathrm{d} x=\int\limits_{\gamma_R}\frac{1}{x^2+1} \mathrm{d} x+\int\limits_{R}^{R}\frac{1}{x^2+1} \mathrm{d} x</math></blockquote>
<math> \oint\limits_{H}\frac{1}{x^2+1} \mathrm{d} x=\int\limits_{\gamma_R}\frac{1}{x^2+1} \mathrm{d} x+\int\limits_{R}^{R}\frac{1}{x^2+1} \mathrm{d} x</math></blockquote>


the other half of the contour, <math>\gamma_R</math></blockquote>, can be represented as the equation :
the other half of the contour, <math>\gamma_R</math></blockquote>, can be represented as the equation :

Revision as of 14:42, 21 July 2023

The residue theorem, invented by Cauchy, is a method of evaluating definite integrals.


Consider the following contour in the complex plane :



where R is a limit going to infinity...or something


Let's find

the first half of the contour is a straight line that goes from -R to R hence, this can be represented as, (H is the entire contour, because i said so)



the other half of the contour, , can be represented as the equation : where v is a variable that goes from to 0